4x^2-5=2x^2-3x=

Solution for 4x^2-5=2x^2-3x= equation:

4x^2-5=2x^2-3x=

We move all terms to the left:

4x^2-5-(2x^2-3x)=0

We get rid of parentheses

4x^2-2x^2+3x-5=0

We add all the numbers together, and all the variables

2x^2+3x-5=0

a = 2; b = 3; c = -5;
Δ = b2-4ac
Δ = 32-4·2·(-5)
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{49}=7$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-7}{2*2}=\frac{-10}{4}
=-2+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+7}{2*2}=\frac{4}{4}
=1
$